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Timeline for A generalized Thom Isomorphism

Current License: CC BY-SA 3.0

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Mar 11, 2014 at 9:33 comment added Liviu Nicolaescu I used the term "ill posed" with a nod to math-phyz where it has a precise meaning.
Mar 11, 2014 at 6:52 comment added Mark Grant @LiviuNicolaescu: I agree with you on some level. I was just trying to understand the sentence in your answer. (To me, it seems that what the OP proposed did work, even if it turned out to be trivial.)
Mar 9, 2014 at 10:19 comment added Liviu Nicolaescu Also, I'm not opposed to the question. I think that it had an easy answer that could have picked up from even a superficial reading of the proof of Thom iso.
Mar 9, 2014 at 10:11 comment added Liviu Nicolaescu As opposed to this question, the Thom isomorphism is a central part of a deep and far reaching phenomenon called duality. I know of two rather different ways duality was generalized: to the cohomology of arbitrary sheaves (Verdier) and to other cohomology theories. E.g. the Bott periodicity is a special case of Thom iso for K-theory. It corresponds to the case X= point. In all incarnations of Thom iso, the case X=point is fundamental.
Mar 9, 2014 at 9:40 comment added Mark Grant @LiviuNicolaescu: Could you please explain your objection to the question? As far as I see it, Alex Degtyarev's answer describes what happens (even when $X$ is a point). The question has an easy answer, but one which I can imagine being useful to know, and it seems to be a genuine generalization of the Thom isomorphism.
Mar 7, 2014 at 11:55 comment added Liviu Nicolaescu Then read csrefully any proof of the Thom isomorphism theorem to understand why your question is ill posed.
Mar 7, 2014 at 0:05 comment added Ali Taghavi at this time the book is not available to me. do you remember a particular statment or proposition in the book related to my question?
Mar 6, 2014 at 23:22 comment added Liviu Nicolaescu This question goes nowhere. Have a look at the book by Bott and Tu Differential forms in algebraic topology.
Mar 6, 2014 at 23:10 comment added Ali Taghavi Yes the particular case X=point shows that the "right side" can not depend only on $X$, but it depend also on the number of deleted points. So i am trying to underestand the first answer to my question.In fact my question: Does my propose leads to triviality?
Mar 6, 2014 at 0:18 review Low quality posts
Mar 6, 2014 at 3:46
Mar 6, 2014 at 0:02 history answered Liviu Nicolaescu CC BY-SA 3.0