Timeline for Does every null-homologous surface bound, part deux
Current License: CC BY-SA 3.0
6 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Mar 7, 2014 at 9:14 | comment | added | user126154 | The classical method of Kneser for eliminating singularities should work in this setting. (cite: a la recherche de la topologie perdue, page 61. zbmath.org/?q=an:03962761) | |
| Mar 6, 2014 at 12:45 | comment | added | Igor Rivin | @MarkGrant No, now that you mention it, it is not clear, though I have a bit set that this is true, for some reason... | |
| Mar 6, 2014 at 7:20 | comment | added | Mark Grant | Good question! There should be some way to take the null-homology and resolve the singularities, and perhaps this can be made algorithmic, but I don't see how this should be related to the spectral sequence. One question: is it clear that the surface bounds a submanifold? I don't see why the 3-manifold needs to be embedded. | |
| Mar 5, 2014 at 19:38 | comment | added | Ryan Budney | The spectral sequence should give you an algorithm in principle. In low dimensions like that, the obstructions are usually readily dealt with quite explicitly. A not very effective procedure to find the 3-manifold would be to take the exterior of the surface, triangulate it and look for the 3-manifold as a "normal" 3-manifold in that triangulation. One might have to subdivide the triangulation for the 3-manifold to appear as a vertex-normal solution. | |
| Mar 5, 2014 at 19:26 | history | asked | Igor Rivin | CC BY-SA 3.0 |