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Feb 20, 2010 at 21:31 vote accept vonjd
Feb 20, 2010 at 21:26 comment added José Figueroa-O'Farrill $\mathbb{E}$ is a linear operation. It is after all integration with respect to a probability measure. The parameter $\theta$ is auxiliary -- it is a constant from the point of view of integration.
Feb 20, 2010 at 21:06 comment added vonjd Thank you - why are you allowed to do that (interchanging differentiation and $\mathbb{E}$)? And why are you allowed to pull out the ${1\over k!}$?
Feb 20, 2010 at 20:41 history answered José Figueroa-O'Farrill CC BY-SA 2.5