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Mar 5, 2014 at 17:39 vote accept Greg Zitelli
Mar 3, 2014 at 14:52 history edited Gerald Edgar CC BY-SA 3.0
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Mar 3, 2014 at 14:44 comment added Gerald Edgar When questions are changed, answers may not longer apply... editing to say I answered the original question.
Mar 3, 2014 at 14:43 history edited Gerald Edgar CC BY-SA 3.0
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Mar 3, 2014 at 9:01 comment added Jean Van Schaftingen In the definition above, $M^p$ is defined by the limsup being finite, so I think that $M^p$ is indeed a vector space. However your example might show that the semi-norm induced by this limsup on $M^2$ is not Euclidean as it would not satisfy the parallelogram identity.
Mar 2, 2014 at 20:19 history edited Gerald Edgar CC BY-SA 3.0
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Mar 2, 2014 at 20:05 history answered Gerald Edgar CC BY-SA 3.0