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Mar 6, 2014 at 15:22 comment added user8991 i do not understand your question. if $f$ is a rotation of angle $\alpha$, then $f^n(0)=n \alpha$, and i want an analogous formula when $f$ is an interval exchange (or at least, some information of some kind).
Mar 5, 2014 at 14:44 comment added user39115 I guess, but I am not sure, that by explicit formula you mean a computable function F that depends on f^k(0), for k<m and m is fixed, such that F(n)=f^n(0). I think you need to specify what exactly you want to mean by explicit formula.
S Mar 5, 2014 at 14:43 history suggested CommunityBot CC BY-SA 3.0
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Mar 5, 2014 at 14:38 review Suggested edits
S Mar 5, 2014 at 14:43
Mar 1, 2014 at 11:58 comment added user8991 is Rauzy-veech induction relevant for this problem?
Mar 1, 2014 at 10:23 comment added user8991 maybe you are right, replace "it implies" by "it is implied". I am only interested in the case of rational lengths.
Mar 1, 2014 at 1:08 comment added Douglas Zare Why would the lengths of the intervals have to be rational? The implication in the other direction is obvious, but it seems like you could take a periodic interval exchange map and break it up into one with irrational lengths that is essentially the same. Is that ruled out by the definitions or some other standard assumption?
Feb 28, 2014 at 23:28 comment added user8991 that there exists $n$ such that for any $x$, $f^n(x)=x$. it implies that the lengths of intervals are rational.
Feb 28, 2014 at 17:34 comment added Anthony Quas What do you mean $f$ is periodic? that $f^n(x)=x$ for all $x$ for some $n$?
Feb 28, 2014 at 14:04 comment added user8991 combinat.sagemath.org/doc/reference/combinat/sage/combinat/iet/…
Feb 28, 2014 at 13:57 comment added user8991 en.wikipedia.org/wiki/Interval_exchange_transformation
Feb 28, 2014 at 13:56 comment added Felix Goldberg What's an interval exchange transformation?
Feb 28, 2014 at 13:55 history asked user8991 CC BY-SA 3.0