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Feb 28, 2014 at 13:07 vote accept MthQ
Feb 27, 2014 at 19:22 answer added Nathaniel Johnston timeline score: 5
Feb 27, 2014 at 13:53 comment added MthQ That indeed looks promising, Paglia. $V_n$ and $V_n^*$ both seem to have a simple structure.
Feb 27, 2014 at 13:36 comment added Paglia One possibility for you to compute $L_n^+$ is to find a diagonalization $L_n = V_n D_n V_n^*$ ($L_n$ seems to be diagonalizable in this case, I run some Matlab tests) and then put $L_n^+ = V_n D_n^+ V_n^*$, where the pseudoinverse of the diagonal matrix $D_n$ is easily computable: you just have to take the reciprocal of each non-zero element on the main diagonal, and leave the zeros elements at their own place.
Feb 27, 2014 at 13:18 comment added Carlo Beenakker the pseudoinverse of $L_n$ has some obvious structure, each row or column adds up to zero.
Feb 27, 2014 at 12:48 history edited MthQ CC BY-SA 3.0
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Feb 27, 2014 at 12:25 history asked MthQ CC BY-SA 3.0