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Feb 28, 2014 at 0:01 comment added eric Indeed, in Berger's example we have $p^NL_2+L_1$ contains $p^NT^N$ and hence $p^{N-1}T^{N-1}$... and hence 1, which is not in $L_1$.
Feb 27, 2014 at 11:59 history edited user1688 CC BY-SA 3.0
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Feb 27, 2014 at 10:32 history answered user1688 CC BY-SA 3.0