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Mar 4, 2014 at 21:21 vote accept Anton Kapustin
Feb 27, 2014 at 18:16 comment added Alex Degtyarev Well, that's just the way it is. You need to compute $\def\Sq{\operatorname{Sq}}\Sq^{-1}=1+\Sq^1+\Sq^2+\Sq^2\Sq^1+\ldots$ and use Wu formulas.
Feb 27, 2014 at 16:17 comment added Anton Kapustin Why is u_3=w_1 w_2? I thought there is also w_1^3 and w_3 there.
Feb 27, 2014 at 10:57 history edited Alex Degtyarev CC BY-SA 3.0
Typo in Wu formula corrected ($w\to u$)
Feb 27, 2014 at 8:06 history answered Alex Degtyarev CC BY-SA 3.0