Timeline for Groups of order $p(p^2+1)/2$
Current License: CC BY-SA 3.0
7 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Feb 22, 2014 at 22:00 | comment | added | Lucia | @StefanKohl: Thanks! This is essentially the argument of Erdos, Murty & Murty. | |
| Feb 22, 2014 at 21:56 | comment | added | Stefan Kohl♦ | Ah, o.k.. -- I think your bound $O(\pi(x)/\log \log \log x)$ is really nice. | |
| Feb 22, 2014 at 21:49 | history | edited | Lucia | CC BY-SA 3.0 |
added 252 characters in body
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| Feb 22, 2014 at 21:45 | comment | added | Lucia | @StefanKohl: Oh right; also $n$ is divisible at most by squares of primes (as in Chapman's answer). Note that what I wrote was a necessary condition; but I also edited to include the sufficient condition. | |
| Feb 22, 2014 at 21:02 | comment | added | Stefan Kohl♦ | Concerning the second paragraph: we have $(p^k,p^k-1) = 1$, but for $k \geq 3$ there are nonabelian groups of order $p^k$ -- how does this fit together with what you write? | |
| Feb 22, 2014 at 19:48 | history | answered | Lucia | CC BY-SA 3.0 |