Skip to main content

Given two applications f$f$ and g$g$, denote by R (f, g)$R (f, g)$ the set of Reidemeister classes determined by f$f$ and g$g$ (according to the algebraic definition, on the induced on fundamental groups). And Lev(f, g)$\operatorname{Lev}(f, g)$ the set of conjugacy classes of lifts of f$f$ and gin$g$ in respect of universal coverings.

I know these two ways of defining classes and Reidemeister number but how do I prove that the cardinal of Lev (f, g)$\operatorname{Lev}(f, g)$ is equal to R (f, g)$R (f, g)$, ie, they produce the same Reidemeister number?

Given two applications f and g, denote by R (f, g) the set of Reidemeister classes determined by f and g (according to the algebraic definition, on the induced on fundamental groups). And Lev(f, g) the set of conjugacy classes of lifts of f and gin respect of universal coverings.

I know these two ways of defining classes and Reidemeister number but how do I prove that the cardinal of Lev (f, g) is equal to R (f, g), ie, they produce the same Reidemeister number?

Given two applications $f$ and $g$, denote by $R (f, g)$ the set of Reidemeister classes determined by $f$ and $g$ (according to the algebraic definition, on the induced on fundamental groups). And $\operatorname{Lev}(f, g)$ the set of conjugacy classes of lifts of $f$ and $g$ in respect of universal coverings.

I know these two ways of defining classes and Reidemeister number but how do I prove that the cardinal of $\operatorname{Lev}(f, g)$ is equal to $R (f, g)$, ie, they produce the same Reidemeister number?

Source Link

Equivalence between the definitions of Reidemeister Coincidence number

Given two applications f and g, denote by R (f, g) the set of Reidemeister classes determined by f and g (according to the algebraic definition, on the induced on fundamental groups). And Lev(f, g) the set of conjugacy classes of lifts of f and gin respect of universal coverings.

I know these two ways of defining classes and Reidemeister number but how do I prove that the cardinal of Lev (f, g) is equal to R (f, g), ie, they produce the same Reidemeister number?