Timeline for Calculating 6j-symbols (aka Racah-Wigner coefficients) for quantum groups
Current License: CC BY-SA 2.5
9 events
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Mar 9, 2010 at 9:38 | vote | accept | Bruce Westbury | ||
Mar 5, 2010 at 14:30 | comment | added | Pavel Etingof | I am not sure what you mean by "Lusztig's tensor product". By fusion operator I mean the one defined in my paper with Varchenko "Exchange dynamical quantum groups", and I don't see how it can be equal to the identity map. Also the fusion and exchange operators depend on the dynamical parameter $\lambda$ which is one of the six j-labels. | |
Mar 5, 2010 at 8:04 | comment | added | Bruce Westbury | I need to clear my desk so I can work through this. Meanwhile; if you use Lusztig's tensor product then the fusion operators are identity maps. This means the 6j-symbols are equal to the 3j-symbols (with respect to this tensor product). Then I think the exchange operator is the R_0-matrix. I am not sure how this helps calculate 6j-symbols. | |
Mar 4, 2010 at 22:13 | comment | added | Pavel Etingof | I edited my answer to explain the relation between 6j symbols and exchange operators. | |
Mar 4, 2010 at 22:13 | history | edited | Pavel Etingof | CC BY-SA 2.5 |
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Mar 4, 2010 at 21:17 | comment | added | Bruce Westbury | It has taken me a while to respond as I had not come across fusion operators or exchange operators. I have found a formula which I almost understand which says that the 6j-symbols can be calculated from 3j-symbols using the fusion operator. I have not seen a relation between the 6j-symbols and the exchange operator. | |
Feb 19, 2010 at 18:27 | history | edited | Pavel Etingof | CC BY-SA 2.5 |
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Feb 19, 2010 at 17:40 | history | edited | Pavel Etingof | CC BY-SA 2.5 |
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Feb 19, 2010 at 17:24 | history | answered | Pavel Etingof | CC BY-SA 2.5 |