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Mar 9, 2010 at 9:38 vote accept Bruce Westbury
Mar 5, 2010 at 14:30 comment added Pavel Etingof I am not sure what you mean by "Lusztig's tensor product". By fusion operator I mean the one defined in my paper with Varchenko "Exchange dynamical quantum groups", and I don't see how it can be equal to the identity map. Also the fusion and exchange operators depend on the dynamical parameter $\lambda$ which is one of the six j-labels.
Mar 5, 2010 at 8:04 comment added Bruce Westbury I need to clear my desk so I can work through this. Meanwhile; if you use Lusztig's tensor product then the fusion operators are identity maps. This means the 6j-symbols are equal to the 3j-symbols (with respect to this tensor product). Then I think the exchange operator is the R_0-matrix. I am not sure how this helps calculate 6j-symbols.
Mar 4, 2010 at 22:13 comment added Pavel Etingof I edited my answer to explain the relation between 6j symbols and exchange operators.
Mar 4, 2010 at 22:13 history edited Pavel Etingof CC BY-SA 2.5
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Mar 4, 2010 at 21:17 comment added Bruce Westbury It has taken me a while to respond as I had not come across fusion operators or exchange operators. I have found a formula which I almost understand which says that the 6j-symbols can be calculated from 3j-symbols using the fusion operator. I have not seen a relation between the 6j-symbols and the exchange operator.
Feb 19, 2010 at 18:27 history edited Pavel Etingof CC BY-SA 2.5
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Feb 19, 2010 at 17:40 history edited Pavel Etingof CC BY-SA 2.5
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Feb 19, 2010 at 17:24 history answered Pavel Etingof CC BY-SA 2.5