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May 6, 2018 at 13:01 comment added Pietro Majer Also: mathoverflow.net/questions/199158/…
Feb 22, 2014 at 15:10 comment added PLG Thanks for the link! However it seems to me that Picard and Vessiot's theory answers the question negatively when it comes to elementary means but, as pointed by Bryant below, a solution is exactly expressible if one allows for integration procedures. I just realised that indeed, the solution to any system $A(t)v(t)=\dot{v}(t)$ is exactly expressible in terms of the solutions to a $finite$ number of linear Volterra equations of the 2nd kind.
Feb 21, 2014 at 15:08 answer added username timeline score: 1
Feb 21, 2014 at 13:31 comment added Piyush Grover Relevant:mathoverflow.net/questions/140849/solution-of-linear-ode/…
Feb 21, 2014 at 12:32 answer added Robert Bryant timeline score: 9
Feb 21, 2014 at 10:24 comment added PLG Is this series expansion explicitly known at all orders ? And I don't mean something like the Dyson series, I mean something that actually allows you to obtain an explicit analytical form for order $n$.
Feb 21, 2014 at 7:13 comment added Pietro Majer You have a series expansion for $M$, and in general I'm afraid this is "the best one can hope for".
Feb 20, 2014 at 22:19 answer added Bazin timeline score: 3
Feb 20, 2014 at 21:15 comment added Alex Degtyarev No hope. Say, any second order linear equation can be converted to a system like yours. But even simplest equations don't have "closed form" solutions.
Feb 20, 2014 at 21:06 history asked PLG CC BY-SA 3.0