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Mar 9, 2018 at 22:02 comment added Y M $D_3=A_3$ by convention
Jun 28, 2017 at 21:59 comment added LSpice $SO(4, 2)$ is of type $D_3$, not $A_3$.
Feb 23, 2014 at 18:52 comment added Y M I found a reference...thanks to all who responded for their useful comments and valuable insights
Feb 23, 2014 at 18:51 answer added Y M timeline score: 1
Feb 20, 2014 at 20:01 comment added Y M I was following the authors terminology; which I agree is not precise. I'm overlooking this imprecision with the assumption that there's something useful here to learn. I added some additional background from the paper above; hopefully that's of value.
Feb 20, 2014 at 19:59 history edited Y M CC BY-SA 3.0
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Feb 20, 2014 at 19:50 history edited Y M CC BY-SA 3.0
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Feb 20, 2014 at 14:01 comment added Jim Humphreys Though I think I understand what "repreentation space" means here, Ben's comments point to a standard problem of interpreting in mathematical language what goes on in mathematical physics. Most of the work here is probably involved in translating the problem carefully into mathematics, where much is known about finite dimensional representations. (However, the real Lie groups add an extra layer of complication.)
Feb 20, 2014 at 9:24 comment added Ben Webster This question is really unclear. What do you mean by representation space (a space of representations, or a space which is a representation)? I'm also not sure what "the number of operators such their eigenvalues sufficiently label all state vectors" is supposed to mean. If you have a collection of operators whose joint spectrum on a finite dimensional space is simple (my best guess for what "sufficiently label all state vectors" means), then any generic linear combination of them also has simple spectrum.
Feb 20, 2014 at 6:10 review First posts
Feb 20, 2014 at 6:12
Feb 20, 2014 at 5:53 history asked Y M CC BY-SA 3.0