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Feb 18, 2014 at 18:02 comment added Andrea Mori $\binom{\tau^\prime}1=\binom{a^{-1}(\tau)}1=j(a^{-1},\tau)^{-1}a\binom\tau1$
Feb 18, 2014 at 17:54 comment added Pierre MATSUMI I think in the answer, $j(a^{-1}, \tau)^{-1}$ should be replaced by $j(a^{-1}, \tau)$. I am not sure but I almost got hold of what the answerer is teaching me. Very many thanks.
Feb 18, 2014 at 16:58 comment added Pierre MATSUMI Thanks. Anyway, is it OK that I think ${\Bbb C}^2/{\cal O}(\tau,1)^t \cong {\Bbb C}^2/{\cal O}(\tau',1)^t$?
Feb 18, 2014 at 13:42 history edited Andrea Mori CC BY-SA 3.0
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Feb 18, 2014 at 13:26 history answered Andrea Mori CC BY-SA 3.0