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Feb 16, 2014 at 0:52 comment added R.P. Yes, I agree with that (and with your parenthetical statement as well). This is the reason that I later inserted the hedge phrase "at least in this sense". :)
Feb 16, 2014 at 0:50 comment added David E Speyer With a cusp, the preimage of the singular point is non-reduced. With a node, the preimage of the singular point is two points. Here it is neither, but rather an extension of the residue field. As I spell out further in my answer, I think neither one is a good comparison. (Although, if forced, I would say the node is closer.)
Feb 16, 2014 at 0:37 history edited R.P. CC BY-SA 3.0
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Feb 15, 2014 at 22:21 history edited R.P. CC BY-SA 3.0
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Feb 15, 2014 at 22:00 history answered R.P. CC BY-SA 3.0