Timeline for Deconvolution of sum of two random variables
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 26, 2014 at 20:22 | vote | accept | Philip | ||
| Feb 25, 2014 at 17:45 | answer | added | Philip | timeline score: 3 | |
| Feb 16, 2014 at 21:39 | answer | added | Dave31415 | timeline score: 2 | |
| Feb 14, 2014 at 22:26 | comment | added | user46979 | Have you looked at the Wikipedia articles "deconvolution" and "blind deconvolution"? Sorry I can't post this as a comment either. [converted to comment -- mods] | |
| Feb 14, 2014 at 17:11 | answer | added | Robert | timeline score: 6 | |
| Feb 14, 2014 at 13:40 | comment | added | Jochen Wengenroth | At least in principle you can calculate all moments $E(X^n)$ by a recursion from the moments of $Z$. | |
| Feb 14, 2014 at 13:39 | comment | added | Jochen Wengenroth | @mike: If $c$ is fixed this problem disappears. | |
| Feb 14, 2014 at 13:13 | comment | added | mike | you have an identification issue since if e.g. X,Y normal mean 0 the result is normal, mean 0 variance $\sigma^2( 1 + c^2)$, so more than 1 $c, \sigma$ pair can correspond to the dist. of Z. | |
| Feb 14, 2014 at 13:02 | comment | added | Thomas Rippl | Shouldn't it be $\sum_{d\in D} g(d)g((x-d)/c)$ ? | |
| Feb 14, 2014 at 12:20 | review | First posts | |||
| Feb 14, 2014 at 12:27 | |||||
| Feb 14, 2014 at 12:03 | history | asked | Philip | CC BY-SA 3.0 |