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Feb 14, 2014 at 3:25 comment added Fantastic I think the calculations are correct, though It does NOT tell us the decay rate. Now we have $$\|u(t)\|^2\leq C\,\exp^{-\lambda \int_0^tm(s)ds}$$ Unless we know a lower bound for $m(t)$, it is as hard as the original question. Thanks for the elegant calculation though.
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Feb 13, 2014 at 20:10 review First posts
Feb 13, 2014 at 20:13
Feb 13, 2014 at 20:03 comment added Michael Renardy He specified that n is the inward normal, so you have the opposite sign. That is, the heat flux is outward, and one should expect decay rather than blowup.
Feb 13, 2014 at 19:54 history answered SetHead CC BY-SA 3.0