Timeline for A question about small cardinals related to Michael's Problem
Current License: CC BY-SA 3.0
4 events
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| Feb 13, 2014 at 19:37 | comment | added | Andreas Blass | Instead of building a strong scale from scratch, you could modify an existing scale, which is well-known to exist if $\mathfrak b=\mathfrak d$. If $\{g_\alpha:\alpha<\kappa\}$ is a scale, then a strong scale (increasing with respect to $\leq^*$ but dominating with respect to $\leq$) is given by setting, for $\alpha=\lambda+n$ as in Ramiro's answer, $f_\alpha(x)=xg_\lambda(x)+n$. | |
| Feb 13, 2014 at 18:43 | vote | accept | Renan Mezabarba | ||
| Feb 13, 2014 at 18:39 | history | edited | Ramiro de la Vega | CC BY-SA 3.0 |
added 539 characters in body
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| Feb 13, 2014 at 18:12 | history | answered | Ramiro de la Vega | CC BY-SA 3.0 |