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Feb 12, 2014 at 16:22 vote accept D. Kelleher
Feb 12, 2014 at 5:12 comment added D. Kelleher @Carl, I think I see what you mean now, I have been able to use it to get a recurrence relation for the coefficients. Thank you.
Feb 12, 2014 at 2:18 answer added Alexandre Eremenko timeline score: 7
Feb 11, 2014 at 18:46 comment added D. Kelleher @Carl I'm not sure what you mean, what am I equating the coefficients of the power series of $h$ with?
Feb 11, 2014 at 18:19 comment added user25199 Can't you just write down a power series for $h$ and equate coefficients, starting $h(z)=z+h''(0)z^2/2+\ldots$?
Feb 11, 2014 at 16:53 history asked D. Kelleher CC BY-SA 3.0