Timeline for Can one determining the p-adic lattice just from the values of the quadratic form on a p-group?
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| Feb 5, 2014 at 22:44 | comment | added | Alex Degtyarev | @HNuer: Yes, the answer is "you cannot", of course unless you know something. The universal counterexample, easier than yours, is the pair $[2]$ and $[10]$ of $(1\times1)$-matrices: they are just different! More details on your particular problem may help: there may be extra data hidden somewhere. | |
| Feb 5, 2014 at 22:05 | comment | added | HNuer | But how could you determine the discriminant without knowing the lattices ahead of time? In the specific situation I'm in, I have quadratic forms on some finite groups, and I need to know which p-adic lattice corresponds to my specific p-group and its quadratic form. Is the answer really just that I can't determine this? | |
| Feb 5, 2014 at 21:45 | history | answered | Alex Degtyarev | CC BY-SA 3.0 |