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Feb 12, 2014 at 15:49 vote accept Manuel Bärenz
Feb 12, 2014 at 15:49 comment added Manuel Bärenz Ah, in other words, the duals only depend on the spherical element in the algebra, which can be written in terms of $q$?
Feb 11, 2014 at 19:10 comment added Kevin Walker I think that one can write out bases and relations for the tensor category structure on $Rep(U_q(sl_2))$ using only powers of $q$, but that the braiding requires $q^{1/2}$. Check out Kuperberg's "spider" paper (arxiv.org/pdf/q-alg/9712003v1.pdf) and compare the tensor category relation on pages 12-14 with the braidings on page 16.
Feb 11, 2014 at 18:54 comment added Manuel Bärenz When I look at the triangular element of $U_q SL(2)$ in Kassel's book, I find the $q^{1/2}$, but don't the duals depend on the triangular element as well?
Feb 7, 2014 at 13:45 comment added Kevin Walker For most (all?) choices of $\xi$, the twist functor will change.
Feb 7, 2014 at 8:18 comment added Chris Schommer-Pries Does this change effect the twist functor? or can that be taken to be the same in both cases?
Feb 5, 2014 at 16:26 history answered Kevin Walker CC BY-SA 3.0