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Feb 7, 2014 at 19:45 vote accept Alem
Feb 7, 2014 at 17:24 answer added ahmed timeline score: 1
Feb 6, 2014 at 9:55 comment added Alem If we expand it in Taylor series, we could cut finitely many terms and so these would be in $L^{p}\left(\mathbb{D}\right)$. So we could approximate it with some finite part of it which is obviously in $L^{\mathbb{p}}\left(\mathbb{D}\right)$. Really interesting.
Feb 6, 2014 at 9:47 comment added Willie Wong Have you thought about $f = 1/(z-1)^2$?
Feb 6, 2014 at 9:39 comment added Alem It is Lebesgue space. These spaces are called Bergman spaces. Let us consider the unit ball $\mathbb{D}$. If we have a function that is analytic on $\mathbb{D}$. Is there any analytic function $g\in L^{p}\left(\mathbb{D}\right)$ such that $g$ approximates $f$ on $\mathbb{D}$ in any way? Are there any results on this topic?
Feb 6, 2014 at 9:32 comment added Willie Wong What exactly is $L^p$ here? The usual Lebesgue space with index $p$, or something else? If so, everything boils down to boundary behaviour, no? Then point-wise approximation feels very unlikely as it does not affect the blow-up rate.
Feb 5, 2014 at 16:06 review Close votes
Feb 6, 2014 at 10:45
Feb 5, 2014 at 14:26 comment added Alem The domain is just like that that Lp of analytic functions of that domain is not zero. I didn't find anything, nor for the ball, nor for the half space etc...So any particular case would be ok for me. I would like pointwise approximation in the sense that for analytic function $f$ we have other analytic function $g\in L^{p}$ such that $\vert f-g\vert<\epsilon$.
Feb 5, 2014 at 13:45 history asked Alem CC BY-SA 3.0