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Feb 9, 2014 at 6:10 vote accept Alex Ravsky
Feb 9, 2014 at 6:10 comment added Alex Ravsky @BenjaminSteinberg Thanks a lot. My friend said that you are a well-known specialist in this area and he is happy with your answer.
Feb 4, 2014 at 19:13 comment added Benjamin Steinberg The op was not clear on this point.
Feb 4, 2014 at 18:58 comment added Misha I see, I was thinking about the regular trivalent tree.
Feb 4, 2014 at 15:14 comment added Benjamin Steinberg @Misha, If the OP means by binary tree the Cayley graph of the free monoid on 2-generators, then the root is the only degree 2 vertex and so must be fixed.
Feb 4, 2014 at 8:52 comment added Misha One more thing: The (almost) full automorphism group $Aut_+(T)$ is an HNN extension of $Aut(T,r)$ (the group described in your answer), where $r$ is a fixed vertex of $T$ (a "root"). Here $Aut_+(T)$ is the subgroup of $Aut(T)$ of index 2 consisting of automorphisms acting without inversions. The edge subgroup here is also well-understood, it is isomorphic to the direct product $Aut(T,r)\times Aut(T,r)$.
Feb 3, 2014 at 23:14 history edited Benjamin Steinberg CC BY-SA 3.0
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Feb 3, 2014 at 18:35 history answered Benjamin Steinberg CC BY-SA 3.0