Timeline for Uncountable atomless subalgebras of the Boolean algebra of all Jordan measurable sets in [0,1]
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| Dec 2, 2016 at 0:41 | answer | added | Goldstern | timeline score: 2 | |
| Feb 8, 2014 at 0:20 | comment | added | Ameen | @EmilJeřábek Yes, the inclusion map of $\mathcal B$ is not onto but this is not enough to say they are not isomorphic, because inclusion map of odd numbers in $\Bbb N$ is also not onto but they are isomorphic. | |
| Feb 3, 2014 at 20:38 | comment | added | Emil Jeřábek | As for (2), $\mathcal A/N$ is itself an atomless algebra. I see no reason why it should be isomorphic to $\mathcal B$. Certainly the natural inclusion of $\mathcal B$ in $\mathcal A/N$ is not onto. | |
| Feb 3, 2014 at 20:10 | history | edited | j.c. | CC BY-SA 3.0 |
improve title?
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| Feb 3, 2014 at 19:36 | vote | accept | Ameen | ||
| Feb 3, 2014 at 17:07 | answer | added | Joel David Hamkins | timeline score: 6 | |
| Feb 3, 2014 at 17:02 | history | edited | Ameen | CC BY-SA 3.0 |
edited body
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| Feb 3, 2014 at 17:02 | comment | added | Ameen | @JoelDavidHamkins Oh yes, exactly. Thanks for letting me know. I will correct it. | |
| Feb 3, 2014 at 17:00 | comment | added | Joel David Hamkins | Do you mean $\mu(\partial(A))=0$ in the definition of Jordan measurable? | |
| Feb 3, 2014 at 15:32 | history | asked | Ameen | CC BY-SA 3.0 |