Timeline for When is a subgroup of a Lie group itself a Lie group?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 2, 2014 at 18:51 | answer | added | Ben McKay | timeline score: 0 | |
| Feb 2, 2014 at 12:51 | answer | added | Claudio Gorodski | timeline score: 3 | |
| Feb 2, 2014 at 10:31 | history | edited | Samuel Monnier | CC BY-SA 3.0 |
On second thought, the theorem 1 which was linked is probably not useful when specifically considering subgroups endowed with the induced topology.
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| Feb 2, 2014 at 10:29 | comment | added | Samuel Monnier | Yes, I assume that the topology is the induced topology. | |
| Feb 2, 2014 at 10:08 | comment | added | user43326 | Well, if you consider things like $\mathbb R$ embedded in the torus, it sounds extremely unlikely that you get a necessary and sufficient condition. Do you suppose that the topology is the induced topology? | |
| Feb 2, 2014 at 10:03 | comment | added | Samuel Monnier | Anything going beyond the information above would be interesting. Of course, a necessary and sufficient condition would be great, but it's maybe too much to hope for. | |
| Feb 2, 2014 at 9:57 | comment | added | user43326 | Are you looking for a necessary and sufficient condition, or just a nice sufficient condition? | |
| Feb 2, 2014 at 9:32 | history | asked | Samuel Monnier | CC BY-SA 3.0 |