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Timeline for Is $G/T$ a projective variety?

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S Dec 7, 2014 at 15:49 history suggested Ali Taghavi CC BY-SA 3.0
I add a few words
Dec 7, 2014 at 15:37 review Suggested edits
S Dec 7, 2014 at 15:49
Oct 30, 2014 at 15:43 vote accept CommunityBot
Feb 2, 2014 at 14:30 comment added Jim Humphreys @Daniel: My offhand reference to BGG here is unhelpful. Instead, the theorem on affine quotients in arbitrary characteristic (and its history) is found in R.W. Richardson's paper Affine coset spaces of reductive algebraic groups, Bull. London Math. Soc. 9 (1977), no. 1, 38–41. For complex semisimple groups (which are Lie groups), this goes back to Matsushima and others. In any case, notation $G/T$ needs context.
Feb 1, 2014 at 23:42 comment added Daniel Pomerleano @JimHumphreys Do you have a precise reference for this paper of Bernstein, Gelfand and Gelfand?
Feb 1, 2014 at 23:14 comment added Jim Humphreys @Hassan: It's easy to answer your question if you make clear at the outset whether your "Lie group" has a structure of algebraic variety (say over the complex field). For a semisimple algebraic group $G$ over $\mathbb{C}$, the algebraic variety $G/T$ for a maximal algebraic torus $T$ is definitely not projective but instead affine. (Bernstein-Gelfand-Gelfand wrote a long paper about this variety.) On the other hand, the real manifold $G/T$ for a compact Lie group $G$ is certainly compact, and is related indirectly to a complex projective flag variety $G/B$ as in the Borel-Weil theorem.
Feb 1, 2014 at 20:26 comment added Denis Nardin I am not sure what do you mean by "is a projective variety". If your group is algebraic there is a natural algebraic variety structure on its quotients, otherwise I do not know. I think you are correct that any complex semisimple Lie group has an algebraic group structure but I'm far from an expert of the subject and I don't want to say something that might be false or misleading.
Feb 1, 2014 at 19:38 answer added Peter Crooks timeline score: 7
Feb 1, 2014 at 19:21 vote accept CommunityBot
Oct 30, 2014 at 15:43
Feb 1, 2014 at 19:20 comment added user21574 We can not define Borel or parabolic subgroups on non-algebraic groups?. also complex semisimple lie groups can not be viewed as complex linear algebraic groups?
Feb 1, 2014 at 19:11 comment added Denis Nardin In the theory of algebraic groups subgroups $H$ such that $G/H$ is a complete variety are called parabolic subgroups. Borel subgroup are characterized as being minimal parabolic subgroup, so in general maximal tori won't be parabolic. See e.g. Springer, Linear Algebraic Groups.
Feb 1, 2014 at 19:10 history edited Ben McKay CC BY-SA 3.0
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Feb 1, 2014 at 19:09 answer added Ben McKay timeline score: 10
Feb 1, 2014 at 19:05 history asked user21574 CC BY-SA 3.0