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Feb 1, 2014 at 15:40 comment added Colin McLarty I mean $-1$ is not a sum of squares in it, or if you prefer it has at least one real embedding. And I do not assume a chosen order or embedding in $\mathbb{C}$
Feb 1, 2014 at 15:33 comment added Kevin Ventullo When you say real, do you mean it has at least one real embedding, or all of its embeddings are real? Or are you fixing ahead of time an embedding of $F$ into $\mathbb{C}$?
Feb 1, 2014 at 15:08 history asked Colin McLarty CC BY-SA 3.0