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Feb 8, 2014 at 5:10 vote accept David Ong
Feb 1, 2014 at 20:27 comment added YCor more generally, such a group is always a semidirect product $\mathbf{R}^k\rtimes (\mathbf{R}^\ell\times K)$, the action being by isometries.
S Feb 1, 2014 at 16:57 history suggested Claudio Gorodski
Retagged question.
Feb 1, 2014 at 16:44 review Suggested edits
S Feb 1, 2014 at 16:57
Feb 1, 2014 at 15:56 answer added Claudio Gorodski timeline score: 3
Feb 1, 2014 at 15:50 comment added YCor The group of motions of the 3-space generated by horizontal translation and a 1-parameter subgroup of vertical screwings is simply transitive but does not contain all vertical translations.
Feb 1, 2014 at 15:06 review First posts
Feb 1, 2014 at 15:16
Feb 1, 2014 at 14:51 history asked David Ong CC BY-SA 3.0