Timeline for Linear independence of the square roots over Q
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Feb 5, 2014 at 21:03 | comment | added | Jan-Christoph Schlage-Puchta | $\pi$ is transcendent, hence $\mathbb{Q}(\pi)$ is isomorphic to the field $\mathbb{Q}(x)$ of rational functions. To show that the numbers $\sqrt{n^2+\pi^2}$ are $\mathbb{Q}$-linearly independent is therefore equivalent to the statement that the functions $x\mapsto\sqrt{n^2+x^2}$ are $\mathbb{Q}$-linearly independent. | |
| Feb 2, 2014 at 18:19 | history | edited | GuyR | CC BY-SA 3.0 |
added 622 characters in body
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| Feb 1, 2014 at 22:49 | comment | added | Anton | Please tell more about your proof. Where the transcendence is used? | |
| Feb 1, 2014 at 13:10 | review | First posts | |||
| Feb 1, 2014 at 13:14 | |||||
| Feb 1, 2014 at 12:51 | history | answered | GuyR | CC BY-SA 3.0 |