Timeline for Linear independence of the square roots over Q
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Feb 1, 2014 at 14:54 | comment | added | Lev Borisov | In particular, all such $c$ would have to be algebraic. | |
Feb 1, 2014 at 13:32 | comment | added | Joe Silverman | @Mike Thank you, I'll fix that typo. | |
Feb 1, 2014 at 13:32 | history | edited | Joe Silverman | CC BY-SA 3.0 |
edited body
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Feb 1, 2014 at 13:32 | comment | added | Joe Silverman | @DavidLoeffler Well, each finite set will corrrespond to the finitely many $c$'s that satisfy $\sum a_n\sqrt{n^2+c^2}=0$. | |
Feb 1, 2014 at 13:06 | comment | added | David Loeffler | It it obvious that the same finite set $\{a_n\}$ can't work for more than one real $c$? | |
Feb 1, 2014 at 12:31 | comment | added | mme | Minor nitpick: your definition of $S_c$ doesn't have $c$ in it. | |
Feb 1, 2014 at 12:12 | history | answered | Joe Silverman | CC BY-SA 3.0 |