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Feb 23, 2014 at 0:35 comment added David Handelman Why don't the results mentioned in my post earn the bounty? A sufficient condition for the condition is that $P = k P'$ where $k \geq d-1$. On the other hand, not even normality is enough to guarantee sufficiency.
Feb 1, 2014 at 21:10 history edited David Handelman CC BY-SA 3.0
added reference
Feb 1, 2014 at 0:08 history edited David Handelman CC BY-SA 3.0
a bit added, to elaborate on the result.
Feb 1, 2014 at 0:00 history answered David Handelman CC BY-SA 3.0