Timeline for Solve $f(x)=\int_{x-1}^{x+1} f(t) \mathrm{d}t$
Current License: CC BY-SA 3.0
11 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Feb 3, 2014 at 23:25 | vote | accept | Ricbit | ||
| Feb 1, 2014 at 19:36 | comment | added | Richard Stanley | See also rand.org/content/dam/rand/pubs/reports/2006/R374.pdf, equation (4). | |
| Feb 1, 2014 at 17:42 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Feb 1, 2014 at 16:47 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Feb 1, 2014 at 16:43 | comment | added | Alexandre Eremenko | Sure. When you differentiate, Fourier transform obtains one new root, $0$. | |
| Feb 1, 2014 at 16:29 | comment | added | Will Sawin | If you want to get from your differentiated equation to the integral equation, the root had better be nonzero. | |
| Feb 1, 2014 at 0:46 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Jan 31, 2014 at 19:15 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Jan 31, 2014 at 19:07 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Jan 31, 2014 at 18:52 | history | answered | Alexandre Eremenko | CC BY-SA 3.0 |