Timeline for Does there exists $f\in A_{\mathbb R}(\mathbb T)$ with $||f||=r$ such that $||e^{if}||=e^{r}$?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Jan 31, 2014 at 16:24 | comment | added | Inquisitive | If $f(t)=-i, t\in \mathbb T$; Then $||f||=1$ and $||e^{if}||=e$. | |
| Jan 31, 2014 at 16:21 | comment | added | Inquisitive | Actually, problem is trivial for complex valued functions; which I have given the counter example there; therefor, I am interested in real valued functions only; | |
| Jan 31, 2014 at 16:19 | comment | added | Francois Ziegler | I don't understand "let $f\in A_{\mathbb R}(\mathbb T)$ such that $\|f\| \leq r$ then $e^{if} \in A_{\mathbb R }(\mathbb T)$". Shouldn't the last $\mathbb R$ be a $\mathbb C$? | |
| Jan 31, 2014 at 16:17 | history | edited | Inquisitive | CC BY-SA 3.0 |
added 9 characters in body
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| Jan 31, 2014 at 16:15 | history | edited | Willie Wong |
added appropriate arxiv top level tag.
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| Jan 31, 2014 at 16:12 | history | asked | Inquisitive | CC BY-SA 3.0 |