Timeline for Inequality between two matrices
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 29, 2014 at 20:34 | comment | added | JMAA | @Jlamprong This is not a place to get your homework done for you, rather research-level mathematics, I just thought I'd help you out. You might also have typed $n\times m$ the wrong way around, or there could be a typo in whereever you got this problem from. Please be willing to put in some work yourself and in future take basic queries that aren't research-level to math.stackexchange.org instead. | |
| Jan 29, 2014 at 20:32 | comment | added | Jlamprong | Yes, but $m\leq n$ so $K$ doesn't have right inverse | |
| Jan 29, 2014 at 12:56 | comment | added | JMAA | @Jlamprong Since $K$ is full rank and has $m\leq n$ then it has a left inverse, as explained here: math.stackexchange.com/questions/108612/…. Since $K^T$ is also of full rank, but with rows and columns swapped it has a right inverse. I realise that these are the wrong inverses, we want the left inverse of $K^T$ and the right inverse of $K$. Are you sure you didn't mean $m>n$? | |
| Jan 29, 2014 at 12:46 | comment | added | Jlamprong | Thanks @JMAA, but what it $(K^T)^{-1}$ and $K^{-1}$? Because $K$ is not invertible and even not sequare | |
| Jan 29, 2014 at 12:42 | history | answered | JMAA | CC BY-SA 3.0 |