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Mar 20, 2016 at 20:37 answer added hänsel timeline score: 3
Jan 29, 2014 at 11:45 comment added user23860 Obviously, $K_0(\alpha)$ and the rest of the mappings are not isomorphisms. Because otherwise it would imply that all $C^\ast$-algebras have isomorphic $K_0$-groups (and $K_1$-groups). My guess is that he has shown that the suspension functor is surjective. Then using the above technique he tries to show that the suspension is injective as well.
Jan 29, 2014 at 1:26 history asked user36116 CC BY-SA 3.0