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Jan 27, 2014 at 16:49 comment added Steven Landsburg @1729: The map is defined by taking a unit to the one-by-one matrix whose only entry is that unit.
Jan 27, 2014 at 16:20 vote accept 1729
Jan 27, 2014 at 16:20 comment added 1729 can you also say how the map $\mathcal{O}_X^\ast \to K_1$ is defined?
Jan 27, 2014 at 16:18 comment added 1729 thanks for your answer. No need of hypercohomology, I edited the question. Do you have some reference for what you explained?
Jan 27, 2014 at 16:11 history answered Steven Landsburg CC BY-SA 3.0