Skip to main content
6 events
when toggle format what by license comment
Mar 9, 2010 at 10:01 vote accept Jan Weidner
Feb 17, 2010 at 20:25 comment added Greg Stevenson Also, you're welcome :) Another thing to add is that compactness may not be enough in general. There are certain smooth compact complex surfaces for which the finite version of Brown representability fails, although again this is not for the category of sheaves that you want to consider. So at least it isn't clear to me what to expect.
Feb 17, 2010 at 20:19 comment added Greg Stevenson Yes - it also considers the derived category of all sheaves of abelian groups. As I said in the comment I am not sure if it is compactly generated or not at the moment.
Feb 17, 2010 at 12:21 comment added Jan Weidner Thank you! I would still be interested, if D(M) is compactly generated for compact M. The paper you mentioned "On The Derived Category of Sheaves on a Manifold" tells us, that D(M) is not compactly gererated for non compact M. However it says nothing about compact M.
Feb 17, 2010 at 11:36 history edited Greg Stevenson CC BY-SA 2.5
deleted 1 characters in body
Feb 17, 2010 at 11:13 history answered Greg Stevenson CC BY-SA 2.5