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Feb 27, 2010 at 1:09 comment added algori Dan -- indeed, I was a bit imprecise on that account. But all imaginable manifolds admit a triangulation (hence, a CW-structure, but not necessarily a PL-structure). And yes, I think the standard proof of the existence of triangulations for smooth manifolds can be adapted to the case with corners.
Feb 27, 2010 at 0:35 comment added Dan Ramras This seems a bit optimistic, in general. Just for ordinary manifolds, it's still an open question whether every closed topological 4-manifold has a CW structure! This is mentioned in Hatcher's book, after Corollary A.12 in the appendix. If your manifolds are smooth, then you're in better shape: all smooth manifolds (even C^1 manifolds) are triangulable. One proof is due to Cairns. Does anyone know the status of these questions for manifolds with corners?
Feb 22, 2010 at 18:34 vote accept mpdude
Feb 20, 2010 at 1:04 comment added algori mpdude -- if you have a submanifold (with corners) of a manifold (with corners), one can equip both with CW structures so that the submanifold becomes a subcomplex, in which case the inclusion is a cofibration. This happens whenever you have a "reasonable" space "of geometric origin" sitting inside another "reasonable" space "of genoetric origin" as a closed subspace.
Feb 20, 2010 at 0:09 comment added mpdude I see, so it just boils down to the fact that I can pick some CW structure on a manifold with corners. Do I need to show that the map $X \to Y$ takes dimension $d$ faces to dimension $d$ faces?
Feb 17, 2010 at 3:43 history answered algori CC BY-SA 2.5