Timeline for approximate coordinates in a one dimensional lattice
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 24, 2014 at 18:21 | comment | added | Sungjin Kim | @mc0e: When $n=2$,if $1$ and $r_2/r_1$ are linearly independent over rational numbers(which is true because of OP's assumption), then $\mathbb{Z}+(r_2/r_1)\mathbb{Z}$ is dense in $\mathbb{R}$. | |
| Jan 24, 2014 at 7:27 | comment | added | mc0e | Floating point numbers are inherently rational, but it becomes important to ask if the answers are constrained by what can be represented (eg number of digits), or if approximate answers are acceptable to some level of accuracy. | |
| Jan 24, 2014 at 7:20 | comment | added | mc0e | i707107: That's clearly not always true if there are irrational numbers involved. eg it's not true if $ x $ is rational and the ratio of $ r _{1} $ to $ r _{2} $ is irrational. | |
| Jan 24, 2014 at 0:23 | comment | added | Sungjin Kim | $n=2$ is sufficient to do this. | |
| Jan 23, 2014 at 17:04 | comment | added | rocksportrocker | Sorry, forgot to say that I have floating point numbers. | |
| Jan 23, 2014 at 16:20 | comment | added | MvG | What kind of real numbers are you talking about? If you mean rationals, then you could multiply by the common denominator then apply Bézout's identity. On the other hand, general real numbers are inherently hard to handle in algorithms. If you have floating point numbers in some computer in mind, then you should make that explicit as well. | |
| Jan 23, 2014 at 16:06 | review | First posts | |||
| Jan 23, 2014 at 16:13 | |||||
| Jan 23, 2014 at 15:48 | history | asked | rocksportrocker | CC BY-SA 3.0 |