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Jan 21, 2014 at 19:39 comment added Noah Schweber Argh, quite right - that's one of those things that sounds totally innocuous to say, but then someone points out that you need to think about it . . . :) Thanks for reminding me (that's one of my favorite results)!
Jan 21, 2014 at 18:44 vote accept Mike Battaglia
Jan 21, 2014 at 16:01 comment added Asaf Karagila Countably many definable where, and how? Recall the result about pointwise definable models (Hamkins, Linetsky, Reitz). In these models every element is definable. Including all $2^{2^{\aleph_0}}$ ultrafilters.
Jan 21, 2014 at 7:19 history answered Noah Schweber CC BY-SA 3.0