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Jan 20, 2014 at 20:41 comment added Anton Petrunin @MarkMeckes: Sure, the question should be formulated better. (BTW now I see that OP did not understand what he was asking.)
Jan 20, 2014 at 18:28 vote accept Alex M.
Jan 20, 2014 at 10:21 comment added Mark Meckes @AntonPetrunin: It certainly doesn't help that the title refers to "isometric embeddings of metric spaces", whereas the question is about something rather different from what that phrase usually means.
Jan 19, 2014 at 23:46 comment added Anton Petrunin @BillJohnson, you have to read further, once you see Nash's theorem you know it.
Jan 19, 2014 at 23:35 comment added Bill Johnson Look at the first sentence in the OP's post and the tags, Anton. How is one supposed to know that isometric embedding does not have its usual meaning in metric geometry and metric spaces?
Jan 19, 2014 at 23:20 comment added Anton Petrunin @GeraldEdgar, good for you, but you should not do it in diffgeometry :)
Jan 19, 2014 at 23:18 comment added Gerald Edgar I (like Bill and Alexandre) read "isometric embedding" as what it says, not something esoteric known only to specialists.
Jan 19, 2014 at 23:07 comment added Anton Petrunin As well as Bill Johnson, you do not read the question to the end.
Jan 19, 2014 at 23:01 review Low quality posts
Jan 19, 2014 at 23:15
Jan 19, 2014 at 22:46 history answered Alexandre Eremenko CC BY-SA 3.0