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Jan 20, 2014 at 9:15 comment added Allen Knutson If you don't require $G$-invariance, maybe you can also figure out whether $G_2/SU(3)$ admits a complex structure...
Jan 20, 2014 at 9:13 comment added Allen Knutson If a Lie group $G$ acts transitively on a symplectic manifold $M$, then $M$ is a cover of a coadjoint orbit of a central extension of $M$. If $G$ is compact connected, then its central extensions are trivial enough and its coadjoint orbits are simply connected, so $M$ is just a coadjoint orbit of $G$, hence Kähler. Which is to say, there are no new examples if the symplectic form is $G$-invariant.
Jan 19, 2014 at 19:28 comment added pod146 In general, no, it does not have to be G-invariant. However, most constructions of a symplectic form on $M$ will automatically produce such an object.
Jan 19, 2014 at 19:08 history edited Ricardo Andrade
replaced deprecated tag 'geometry'; replaced tag 'symplectic-topology' with 'sg.symplectic-geometry'; added tag 'homogeneous-spaces'
Jan 19, 2014 at 19:07 comment added Francois Ziegler You don't require the symplectic form to be $G$-invariant, do you?
Jan 19, 2014 at 19:05 review First posts
Jan 19, 2014 at 19:20
Jan 19, 2014 at 18:50 history asked pod146 CC BY-SA 3.0