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Feb 17, 2010 at 15:58 vote accept Theo Johnson-Freyd
Feb 17, 2010 at 3:47 comment added Chris Schommer-Pries The Baez-Lauda paper is available here: arxiv.org/abs/math/0307200
Feb 16, 2010 at 21:41 history edited Chris Schommer-Pries CC BY-SA 2.5
added a few more details to clarify.
Feb 16, 2010 at 21:28 comment added Chris Schommer-Pries As an additional remark, it is also possible to choose isomorphisms $i(x) \cdot x \cong 1$ in such a way as to be compatible with the isomorphism $x \cdot i(x) \cong 1$. This takes a little more work, but the argument is explained in the paper by Baez and Lauda on 2-groups.
Feb 16, 2010 at 21:22 history answered Chris Schommer-Pries CC BY-SA 2.5