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Jan 15, 2014 at 17:33 comment added Jim Humphreys @Tom: My first comment was too offhand, but the header and question are very confusing. In an adjoint simple group there are no $W$-invariants except 1 in $T$. Maybe the question is about Weyl groups of centralizers of semisimple elements? That was worked out (for any algebraically closed field) in the 1965 IHES paper of Borel-Tits, following Chevalley's study of regular and singular elements in $T$.
Jan 15, 2014 at 12:37 comment added Tom De Medts @Jim: I don't understand your implication "So under the action of W induced by conjugation only the identity element of T is invariant" in your first comment. Could you clarify this?
Jan 15, 2014 at 12:35 answer added Jay Taylor timeline score: 6
Jan 15, 2014 at 12:34 comment added anonymous There was a 1 in the (n+1)st place!
Jan 15, 2014 at 12:22 comment added Jim Humphreys The problem with this example is that the equivalence class of this diagonal matrix in the adjoint group PGL is the identity element. And for the odd special orthogonal group, the negative of the identity matrix is not in this group.
Jan 15, 2014 at 11:59 comment added anonymous The action of the Weyl group for PGL(2) is t--->t^{-1} so indeed -1 is left invariant under the Weyl group?
Jan 15, 2014 at 11:34 comment added Jim Humphreys There is some confusion here. Recall that $W$ is defined to be the normalizer of $T$ modulo the centralizer, while the centralizer is just $T$ itself. So under the action of $W$ induced by conjugation only the identity element of $T$ is invariant. Your examples are mostly incorrect.
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