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Feb 1, 2014 at 8:06 comment added Name @J.Martel Thank you for your comment. It does imply! If $q_1$ and $q_2$ are both regular, and at least one of them is definite then they are simultaneously diagonalizable (see Greub, Linear Algebra, 1967, Third edition, Ch. IX, p.256).
Jan 24, 2014 at 15:01 comment added JHM I don't think your criterion is correct. In particular, $q_1, q_2$ regular and not simultaneously diagonalizable does not imply that either of $q_1, q_2$ are indefinite (which certainly is necessary!).
Jan 13, 2014 at 17:07 history answered Name CC BY-SA 3.0