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lost1
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What I have in mind is that on $(0,T)\times\Omega$, we have a parabolic pde operator $L$, we have unique solution to

$Lu = f$ when f is Hoelder for some coefficient strictly between 0 and 1.

This is a theorem from Friedman's book on pdes. While i can plough through the proofs which were full of estimates, i don't get the intuitions why they work or why wouldn't they work (Or would they?) for an operator such as

$\bigtriangledown u - \partial_{t_1} - \partial_{t_2} = f$$\bigtriangleup u - \partial_{t_1} - \partial_{t_2} = f$

Where f is a suitable function and the domain is something like $(0,T)\times(0,S)\times\Omega$?

The only answer i found regarding intuition was from User's guide to viscosity solution by crandall-ishii-lions page 52. It says

$u_t+ F(x,u,Du,D^2u)=0$ more or less correspond to $\lambda t+ F = 0$ for large $\lambda$.

I don't quite understand what this means? Does it work if we do $u_t+u_s+F = 0$? What is so nice about having a time evolution that does not (or maybe it does, but i am ignorant) work in higher dimensions?

What I have in mind is that on $(0,T)\times\Omega$, we have a parabolic pde operator $L$, we have unique solution to

$Lu = f$ when f is Hoelder for some coefficient strictly between 0 and 1.

This is a theorem from Friedman's book on pdes. While i can plough through the proofs which were full of estimates, i don't get the intuitions why they work or why wouldn't they work (Or would they?) for an operator such as

$\bigtriangledown u - \partial_{t_1} - \partial_{t_2} = f$

Where f is a suitable function and the domain is something like $(0,T)\times(0,S)\times\Omega$?

The only answer i found regarding intuition was from User's guide to viscosity solution by crandall-ishii-lions page 52. It says

$u_t+ F(x,u,Du,D^2u)=0$ more or less correspond to $\lambda t+ F = 0$ for large $\lambda$.

I don't quite understand what this means? Does it work if we do $u_t+u_s+F = 0$? What is so nice about having a time evolution that does not (or maybe it does, but i am ignorant) work in higher dimensions?

What I have in mind is that on $(0,T)\times\Omega$, we have a parabolic pde operator $L$, we have unique solution to

$Lu = f$ when f is Hoelder for some coefficient strictly between 0 and 1.

This is a theorem from Friedman's book on pdes. While i can plough through the proofs which were full of estimates, i don't get the intuitions why they work or why wouldn't they work (Or would they?) for an operator such as

$\bigtriangleup u - \partial_{t_1} - \partial_{t_2} = f$

Where f is a suitable function and the domain is something like $(0,T)\times(0,S)\times\Omega$?

The only answer i found regarding intuition was from User's guide to viscosity solution by crandall-ishii-lions page 52. It says

$u_t+ F(x,u,Du,D^2u)=0$ more or less correspond to $\lambda t+ F = 0$ for large $\lambda$.

I don't quite understand what this means? Does it work if we do $u_t+u_s+F = 0$? What is so nice about having a time evolution that does not (or maybe it does, but i am ignorant) work in higher dimensions?

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lost1
  • 383
  • 3
  • 13

What fails when we try to extend existence and unique for parabolic PDEs for 'PDEs which are 'parabolic in two components''?

What I have in mind is that on $(0,T)\times\Omega$, we have a parabolic pde operator $L$, we have unique solution to

$Lu = f$ when f is Hoelder for some coefficient strictly between 0 and 1.

This is a theorem from Friedman's book on pdes. While i can plough through the proofs which were full of estimates, i don't get the intuitions why they work or why wouldn't they work (Or would they?) for an operator such as

$\bigtriangledown u - \partial_{t_1} - \partial_{t_2} = f$

Where f is a suitable function and the domain is something like $(0,T)\times(0,S)\times\Omega$?

The only answer i found regarding intuition was from User's guide to viscosity solution by crandall-ishii-lions page 52. It says

$u_t+ F(x,u,Du,D^2u)=0$ more or less correspond to $\lambda t+ F = 0$ for large $\lambda$.

I don't quite understand what this means? Does it work if we do $u_t+u_s+F = 0$? What is so nice about having a time evolution that does not (or maybe it does, but i am ignorant) work in higher dimensions?