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Jan 16, 2014 at 13:04 comment added Yue $\mathbb{P}$-a.s. Convergence of the subsequence is not what I want for...
Jan 16, 2014 at 13:03 comment added Yue Borel Cantelli give you the probability of $\limsup$ rather than $\lim$ to be zero, which implies that you could only find a subsequence which converges to zero $\mathbb{P}-a.s.$....
Jan 15, 2014 at 23:34 comment added Thomson Tong But Borel cantelli should tell you that the probability that $\sup_{t\geq 0}(-\Lambda t+\sqrt{\sigma_k}W_t^k)\geq a$ happen for infinitely many $k$ is 0, which is just a.s. convergence, right? Isn't your $W^k_t$ independent?
Jan 12, 2014 at 22:14 comment added Yue That contributes to convergence in probability only but not P-a.s.
Jan 12, 2014 at 14:35 review First posts
Jan 12, 2014 at 14:36
Jan 12, 2014 at 14:17 history answered Thomson Tong CC BY-SA 3.0