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Jan 11, 2014 at 14:10 history closed Michael Renardy
Carlo Beenakker
Olivier Benoist
Stefan Kohl
abx
Needs details or clarity
Jan 11, 2014 at 13:00 comment added Douglas Zare @Taladris: I wonder how one can know this is not a research level question. There are examples of complicated determinants which count interesting quantities such as plane partitions with particular symmetries which can be expressed as $Det(A\pm I)$ where $A$ does not seem complicated, but where finding the characteristic polynomial of $A$ does not seem easy.
Jan 11, 2014 at 13:00 answer added Peter Michor timeline score: 2
Jan 11, 2014 at 12:59 comment added abx $\det(I-A)=1-\mathrm{Tr}(A)+\mathrm{Tr}(\wedge^2A)+\ldots $ - but I agree this is not a question at research level.
Jan 11, 2014 at 12:52 review Close votes
Jan 11, 2014 at 14:12
Jan 11, 2014 at 12:42 comment added Taladris @MichaelRenardy: I wonder how one can know that a formula does not exist. Anyway, the OP is not a research level question.
Jan 11, 2014 at 12:37 review First posts
Jan 11, 2014 at 12:40
Jan 11, 2014 at 12:36 comment added Michael Renardy What are you expecting? A magic formula where none exists?
Jan 11, 2014 at 12:20 history asked sedef kaplan CC BY-SA 3.0