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Jan 11, 2014 at 15:02 comment added Richard Stanley The matrix came from solving the equations $ad-bc=1$, gcd$(a-1,b,c,d-1)=r$, $(a-1)(d-1)-bc=r^2s$. I made the simplifying assumption $b=d=r$, $a-1=\alpha r$, $d-1=\delta r$ and solved.
Jan 11, 2014 at 4:41 comment added Igor Rivin And it does the $Sp(2n, \mathbb{Z}) case, since $SL(2) = Sp(2).$ Truly you are wise in the ways of science.
Jan 11, 2014 at 3:23 comment added Igor Rivin So, presumably that resolves the $SL(n)$ question for any even $n,$ by using this construction in blocks. Does this matrix come from somewhere, or did it just occur to you?
Jan 11, 2014 at 3:17 history answered Richard Stanley CC BY-SA 3.0