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Oct 1, 2020 at 14:22 comment added Will Sawin @red_trumpet As soon as $n>1$, $GL_n (\mathbb Z[i])$ is not finite.
Oct 1, 2020 at 13:59 comment added red_trumpet Is it clear that $Aut(X)$ is always finite?
Jan 11, 2014 at 5:45 comment added abx No, he is right. $GL_1(\Bbb{Z}[i]$ is $\Bbb{Z}[i]^*=\{\pm 1,\pm i\}$.
Jan 11, 2014 at 4:57 comment added user108005 no,say $n=1$,$Aut(X)$ should be the cyclic group generated by $i$.But according to your answer,$Aut(X)=\mathbb{Z}[i]\setminus \{0\}$,so you are wrong.
Jan 11, 2014 at 1:54 history edited Will Sawin CC BY-SA 3.0
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Jan 11, 2014 at 0:07 history answered Will Sawin CC BY-SA 3.0